April 29, 201214 yr FLUENT (0,1,5) PHOBIA (0,2,4) ABACUS (2,1,3) BAKING (1,0,5) ABRUPT (1,2,3) ALBERT (0,2,4)
April 29, 201214 yr FLUENT (0,1,5) PHOBIA (0,2,4) ABACUS (2,1,3) BAKING (1,0,5) ABRUPT (1,2,3) ALBERT (0,2,4) SERENE (1,1,4) TRIBAL (0,3,3) TURTLE (1,1,4)
April 30, 201214 yr FLUENT (0,1,5) PHOBIA (0,2,4) ABACUS (2,1,3) BAKING (1,0,5) ABRUPT (1,2,3) ALBERT (0,2,4) SERENE (1,1,4) TRIBAL (0,3,3) TURTLE (1,1,4) BLOONS (2,0,4) CITRUS (4,0,2) Getting warmer...
April 30, 201214 yr Working on some reasoning here...if BAKING has only one correct letter, then BAI can only have 1 max. In TRIBAL, there are three correct letters, and three of the letters are BAI. If there's no more than 1 correct letter in BAI, then TRL have to have at least 2 correct letters. No more than 2, we see in TURTLE. But if TRL has 2 correct letters, then U and E have to be wrong. This also means that B, A, or I must be correct. Going up to ALBERT: This also has all three of TRL in it, so it has two correct letters right there. Since ALBERT has only two correct letters, that means there's no A or B. Now ABACUS: Three correct letters. Just ruled out A and B, which means the correct letters are CUS. Except we already ruled out U. Hmm. Bleeeeh. I'm supposed to be writing right now! I'm so bad.
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