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Nova Scotia, woot! Go Canada! It's your birthday! Okay, so it's not your birthday but its someone's birthday today so yay *throws confetti*

Posted

Ah. We don't really have states or provinces here in NZ.

I like the Nova but of NS :P

Posted

Apparently the Ark of the Covenant is on Nova Scotia, but I don't know if you can trust the History Channel

Posted

Objects A, B

 

A: speed = constant = 10m/s

B: starts 5 secs after A, starts from rest, acceleration= 1.2m/s squared

 

QUESTIONS:

 

a) what time do the two objects meet (relative to A)

b) at what distance do they meet (relative to A)

 

HINT: use quadratic equation.

 

I don't even know where to start D: Any help would be greatly appreciated

Posted

Objects A, B

 

A: speed = constant = 10m/s

B: starts 5 secs after A, starts from rest, acceleration= 1.2m/s squared

 

QUESTIONS:

 

a) what time do the two objects meet (relative to A)

b) at what distance do they meet (relative to A)

 

HINT: use quadratic equation.

 

I don't even know where to start D: Any help would be greatly appreciated

Okay, since I don't want to solve this for you, I'll just tell you how I'd go about solving this problem.

 

First, you'll want to find the time that the two objects meet. You can use the formula:

Δx=(1/2)at^2+v(i)t

where "Δx" is change in position, "a" is acceleration, "t" is time, and "v(i)" is the initial velocity.

 

You know that Δx is going to be the same in both object A and B at that time, so you can reflect the right side of the equation over and use one side for object A and the other side for object B.

Basically, use:

(1/2)at^2+v(i)t=(1/2)at^2+v(i)t

And plug in the information for object A on one side and object B on the other. You should then get a quadratic equation, which you can use the quadratic formula to solve.

 

Hopefully this'll help. If not, just post again and I'll try to give you more hints ;)

Posted

....you are a GENIUS!! *bows down to your epicness*. Just hold on. I'm trying this now :P

 

*EDIT:

 

Ok. So when you plug everything in...would t be 5 for both cases?

 

So it becomes

 

(1/2)(0)(5)^2 + (10)(5) = (1/2)(1.2)(5)^2 + (V1)(5)

 

.....am I supposed to know V1 for object B? o.0

 

*EDIT (again):

oh wait!

 

So it becomes 10t = (1/2)(1.2)(5)^2 + (V1)(5).....uhh. I think I'm still stuck :S

Posted

Oh, my bad, I misread the problem. It says that object B starts five seconds after object A.

 

So in that case, object A would have traveled 50m by the time object B starts, so to balance the equation you'll need to add 50 to the side you used to plug in the information with object B.

 

Edit:

v(i) for object B would be 0 m/s because it starts from rest.

 

Oh, and you may need to add 5 seconds to your final answer. Hold on, I'm actually going to try to solve it now, just to make sure I'm not misleading you :P

Posted

And wait. So do you know the basics of what I'm supposed to do/find? o.0

 

Kinda. I'm in grade 9, so I got some of it figured out.

 

-coughcollegecough-

 

I understand the basics of vectors, but I can't spell college right.

 

Maybe it's because I'm watching Avatar while posting.

 

NO! JAKE TRIED TO HELP YOU! DON'T TELL HIM TO LEAVE AND NEVER COME BACK!

Posted

....you are a GENIUS!! *bows down to your epicness*. Just hold on. I'm trying this now :P

 

*EDIT:

 

Ok. So when you plug everything in...would t be 5 for both cases?

 

So it becomes

 

(1/2)(0)(5)^2 + (10)(5) = (1/2)(1.2)(5)^2 + (V1)(5)

 

.....am I supposed to know V1 for object B? o.0

 

*EDIT (again):

oh wait!

 

So it becomes 10t = (1/2)(1.2)(5)^2 + (V1)(5).....uhh. I think I'm still stuck :S

No, "t" does not equal 5.

 

When you plug in everything and simplify, you should have:

10t=0.6t^2

 

Divide both sides by "0.6t", and....

 

Disclaimer:

That's how you'd do it if the objects started at the same time. Like I said in my last post, I misread the problem, so hold on...

Posted

Okay, here it is:

Since object B starts 5 seconds after object A, object A will have a 50m "head-start". To compensate for that, add 50 to the side with object B, so you'll have:

10t=0.6t^2+50

But keep in mind that'll mean you're neglecting the first 5 seconds of the scenario, so once you solve for "t", you'll have to add 5 seconds to your final answer.

 

So move the 10t to the other side...

 

***Edit***

Wait a second, the answers to that formula would be two unreal answers, so I might have to think about this again.

Posted

whoa whoa. How'd we get 50 again? o.0 Like how did you know it was a 50m head start? .....I'm sounding like an idiot aren't I? Sorry:(

 

*EDIT:

 

no wait I got it....I think

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