The Score in Blue Posted November 10, 2010 Posted November 10, 2010 Um, sorry to be a noob, but what is NS? Quote
Wembly Posted November 10, 2010 Posted November 10, 2010 Nova Scotia, woot! Go Canada! It's your birthday! Okay, so it's not your birthday but its someone's birthday today so yay *throws confetti* Quote
CAV of Gang Green Posted November 10, 2010 Posted November 10, 2010 Nova Scotia is a province in Canada. Provinces are like states in the US. Happy birthday random person! Quote
The Score in Blue Posted November 10, 2010 Posted November 10, 2010 Ah. We don't really have states or provinces here in NZ. I like the Nova but of NS :P Quote
Tyler. Posted November 10, 2010 Posted November 10, 2010 Apparently the Ark of the Covenant is on Nova Scotia, but I don't know if you can trust the History Channel Quote
CAV of Gang Green Posted November 11, 2010 Posted November 11, 2010 Discovery Channel > National Geographic > History Channel Telling it like it is. Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 anyone here know anything about physics and vectors and can spare a few min to help? :S And we have a history channel? o.0 Quote
CAV of Gang Green Posted November 11, 2010 Posted November 11, 2010 I know about that stuff. What do you need help with? Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 Objects A, B A: speed = constant = 10m/s B: starts 5 secs after A, starts from rest, acceleration= 1.2m/s squared QUESTIONS: a) what time do the two objects meet (relative to A) b) at what distance do they meet (relative to A) HINT: use quadratic equation. I don't even know where to start D: Any help would be greatly appreciated Quote
CAV of Gang Green Posted November 11, 2010 Posted November 11, 2010 Um, might I ask. Are you in collage. I'm just a freshman in high school. Sorry, can't help with that. Not without a proper calculator at least. Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 I'm in gr 11. And that's Ok....*commences the writting of random numbers* -_- And wait. So do you know the basics of what I'm supposed to do/find? o.0 Quote
-Ryan Posted November 11, 2010 Posted November 11, 2010 -coughcollegecough- Anyway... I trust everyone has had a good day so far? Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 gr 11 is college? .......or are YOU in college? :P If you are do you know how to do the question? If not then.....do you know how to do the question? :P Quote
-Ryan Posted November 11, 2010 Posted November 11, 2010 Yup, i'm in college. I'm the dean at Harvard. :D Quote
Tyler. Posted November 11, 2010 Posted November 11, 2010 I GRADUATED college years ago with straight A's in all advanced classes, now I'm the smartest man alive Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 If you're the smartest man alive can you help me with my question? :P Quote
Unstream Posted November 11, 2010 Posted November 11, 2010 Objects A, B A: speed = constant = 10m/s B: starts 5 secs after A, starts from rest, acceleration= 1.2m/s squared QUESTIONS: a) what time do the two objects meet (relative to A) b) at what distance do they meet (relative to A) HINT: use quadratic equation. I don't even know where to start D: Any help would be greatly appreciated Okay, since I don't want to solve this for you, I'll just tell you how I'd go about solving this problem. First, you'll want to find the time that the two objects meet. You can use the formula: Δx=(1/2)at^2+v(i)t where "Δx" is change in position, "a" is acceleration, "t" is time, and "v(i)" is the initial velocity. You know that Δx is going to be the same in both object A and B at that time, so you can reflect the right side of the equation over and use one side for object A and the other side for object B. Basically, use: (1/2)at^2+v(i)t=(1/2)at^2+v(i)t And plug in the information for object A on one side and object B on the other. You should then get a quadratic equation, which you can use the quadratic formula to solve. Hopefully this'll help. If not, just post again and I'll try to give you more hints ;) Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 ....you are a GENIUS!! *bows down to your epicness*. Just hold on. I'm trying this now :P *EDIT: Ok. So when you plug everything in...would t be 5 for both cases? So it becomes (1/2)(0)(5)^2 + (10)(5) = (1/2)(1.2)(5)^2 + (V1)(5) .....am I supposed to know V1 for object B? o.0 *EDIT (again): oh wait! So it becomes 10t = (1/2)(1.2)(5)^2 + (V1)(5).....uhh. I think I'm still stuck :S Quote
Unstream Posted November 11, 2010 Posted November 11, 2010 Oh, my bad, I misread the problem. It says that object B starts five seconds after object A. So in that case, object A would have traveled 50m by the time object B starts, so to balance the equation you'll need to add 50 to the side you used to plug in the information with object B. Edit: v(i) for object B would be 0 m/s because it starts from rest. Oh, and you may need to add 5 seconds to your final answer. Hold on, I'm actually going to try to solve it now, just to make sure I'm not misleading you :P Quote
Tyler. Posted November 11, 2010 Posted November 11, 2010 yeah, uh, Will helped you, and I knew it just didn't want to give it away :whistle: Quote
CAV of Gang Green Posted November 11, 2010 Posted November 11, 2010 And wait. So do you know the basics of what I'm supposed to do/find? o.0 Kinda. I'm in grade 9, so I got some of it figured out. -coughcollegecough- I understand the basics of vectors, but I can't spell college right. Maybe it's because I'm watching Avatar while posting. NO! JAKE TRIED TO HELP YOU! DON'T TELL HIM TO LEAVE AND NEVER COME BACK! Quote
Unstream Posted November 11, 2010 Posted November 11, 2010 ....you are a GENIUS!! *bows down to your epicness*. Just hold on. I'm trying this now :P *EDIT: Ok. So when you plug everything in...would t be 5 for both cases? So it becomes (1/2)(0)(5)^2 + (10)(5) = (1/2)(1.2)(5)^2 + (V1)(5) .....am I supposed to know V1 for object B? o.0 *EDIT (again): oh wait! So it becomes 10t = (1/2)(1.2)(5)^2 + (V1)(5).....uhh. I think I'm still stuck :S No, "t" does not equal 5. When you plug in everything and simplify, you should have: 10t=0.6t^2 Divide both sides by "0.6t", and.... Disclaimer: That's how you'd do it if the objects started at the same time. Like I said in my last post, I misread the problem, so hold on... Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 wow. Thanks so much for all the help so far! I really appreciate it! Quote
Unstream Posted November 11, 2010 Posted November 11, 2010 Okay, here it is: Since object B starts 5 seconds after object A, object A will have a 50m "head-start". To compensate for that, add 50 to the side with object B, so you'll have: 10t=0.6t^2+50 But keep in mind that'll mean you're neglecting the first 5 seconds of the scenario, so once you solve for "t", you'll have to add 5 seconds to your final answer. So move the 10t to the other side... ***Edit*** Wait a second, the answers to that formula would be two unreal answers, so I might have to think about this again. Quote
Kuroida Posted November 11, 2010 Posted November 11, 2010 whoa whoa. How'd we get 50 again? o.0 Like how did you know it was a 50m head start? .....I'm sounding like an idiot aren't I? Sorry:( *EDIT: no wait I got it....I think Quote
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