May 26, 201214 yr PETPET (1, 1, 4) ESPEON (0, 1, 5) DRAGON (0, 1, 5) CRYPTS (0, 4, 2) PYTHON (1, 1, 4) ZIGZAG (1, 0, 5) TYPING (1, 1, 4) COFFIN (0, 0, 6) YERKES (2, 0, 4)
May 26, 201214 yr PETPET (1, 1, 4) ESPEON (0, 1, 5) DRAGON (0, 1, 5) CRYPTS (0, 4, 2) PYTHON (1, 1, 4) ZIGZAG (1, 0, 5) TYPING (1, 1, 4) COFFIN (0, 0, 6) YERKES (2, 0, 4) STARRY (0, 3, 3)
May 28, 201214 yr Teh logic... COFFIN takes out a C, so we have _RYPTS left in CRYPTS--that means exactly one wrong letter left, since there were 4 right letters. In PYTHON, there are only two correct letters. That means between P, Y, and T, there's a minimum of one wrong letter. All three of those were in CRYPTS, so either the P, Y, or T is wrong. That means R and S are definitely right. That means that the one correct letter in ESPEON is an S, so P and E are both wrong. The one correct letter in DRAGON is an R, so D, A, and G are wrong. In PETPET, the P and E are now wrong, so it has to be two Ts. Going back to CRYPTS again, the P was wrong, so RSTY are right. So right now, we have the letters RSTTY. ZIGZAG has one right letter. But I, A, and G are all wrong. So there must be a Z. So my guess now is: STRYTZ.
May 28, 201214 yr Whoops! Sorry Karina. :P And there is something wrong with your logic there, but i won't say what... muahahahahaha. EDIT: i made a few mistakes, guise. sorry, i fixed them. PETPET (1, 1, 4) ESPEON (0, 1, 5) DRAGON (0, 1, 5) CRYPTS (0, 4, 2) PYTHON (1, 1, 4) ZIGZAG (1, 0, 5) TYPING (1, 1, 4) COFFIN (0, 1, 5) YERKES (2, 1, 3) STARRY (0, 3, 3) PEPPER (1, 1, 4) ARGYLE (0, 3, 3) IGNORE (0, 2, 4) PINATA (0, 1, 5) STRYTZ (1, 2, 3)
May 28, 201214 yr PETPET (1, 1, 4) ESPEON (0, 1, 5) DRAGON (0, 1, 5) CRYPTS (0, 4, 2) PYTHON (1, 1, 4) ZIGZAG (1, 0, 5) TYPING (1, 1, 4) COFFIN (0, 1, 5) YERKES (2, 1, 3) STARRY (0, 3, 3) PEPPER (1, 1, 4) ARGYLE (0, 3, 3) IGNORE (0, 2, 4) PINATA (0, 1, 5) STRYTZ (1, 2, 3) PHYSIC (1, 1, 4) SCYTHE (1, 3, 2)
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