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Five Letter Logic


Parry

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Let's see here... I got a new word for you guys...

 

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PIANO (0, 2, 3)

GRAPE (0, 1, 4)

GOALS (0, 0, 5)

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PIANO (0, 2, 3)

GRAPE (0, 1, 4)

GOALS (0, 0, 5)

PINTO (0, 3, 2)

PRIME (0, 2, 3)

BROKE (0, 1, 4)

STRIP (0, 2, 3)

DEATH (0, 2, 3)

TAXES (0, 2, 3)

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With the letters given away, there are only four possible answers:

 

Unite, Untie, Twine, and Feint.

 

Unfortunately, if you take letter position into account, none of those can possibly be correct.

 

This is my reasoning:

 

T is definitely in the word, and A definitely isn't (Pinto had 3 correct, Piano has 2 correct, the only letter change that happened was that A was switched to T)

All the letters in the word "Goals" are incorrect.

 

Removing all the incorrect letters and highlighting T as correct:

 

PI_N_ (0, 2, 3) (P, I, or N) choose 2

_R_PE (0, 1, 4) (R, P or E) choose 1

_ _ _ _ _ (0, 0, 5)

PINT_ (0, 3, 2) (P, I, or N) choose 2

PRIME (0, 2, 3) (P, R, I, M, or E) choose 2

BR_KE (0, 1, 4) (B, R, K, or E) choose 1

_TRIP (0, 2, 3) (R, I, or P) choose 1

DE_TH (0, 2, 3) (D, E, or H) choose 1

T_XE_ (0, 2, 3) (X or E) choose 1

 

Note: T is NOT in the 1st, 2nd or 4th positions (must be in either the 3rd or 4th position)

 

The last word gives us a choice of either X or E being correct. I am going to assume that E is correct, giving me this:

 

PI_N_ (0, 2, 3) (P, I, or N) choose 2

_R_PE (0, 1, 4) done (R and P eliminated)

_ _ _ _ _ (0, 0, 5) done

PINT_ (0, 3, 2) (P, I, or N) choose 2

PRIME (0, 2, 3) (P, I, or M) choose 1

BR_KE (0, 1, 4) done (B, R and K eliminated)

_TRIP (0, 2, 3) (R, I, or P) choose 1

DE_TH (0, 2, 3) done (D and H eliminated)

T_XE_ (0, 2, 3) done (X eliminated)

 

This eliminates R, P, B, K, D, H, and X.

 

Note: E is not in the 2nd, 4th or 5th positions.

 

Since P was eliminated, [PI_N_ (0, 2, 3) and PINT_ (0, 3, 2)] tell us that both I and N are correct, giving us this:

 

 

 

PI_N_ (0, 2, 3) done

_R_PE (0, 1, 4) done

_ _ _ _ _ (0, 0, 5) done

PINT_ (0, 3, 2) done

PRIME (0, 2, 3) done (M eliminated)

BR_KE (0, 1, 4) done

_TRIP (0, 2, 3) done

DE_TH (0, 2, 3) done

T_XE_ (0, 2, 3) done

 

Total eliminated: G, O, A, L, S, P, B, R, K, D, H, M, and X.

 

Notes: I is not in the 2nd, 3rd, or 4th positions.

N is not in the 3rd or 4th positions.

 

We now know 4/5 letters T, E, I, and N.

 

Compile the notes about positions:

 

T is not in the 1st, 2nd or 4th positions

E is not in the 2nd, 4th or 5th positions.

I is not in the 2nd, 3rd, or 4th positions.

N is not in the 3rd or 4th positions.

 

Conclusions:

-Since none of the above letters can be in the 4th position, it is safe to assume that the unknown 5th letter is there.

-Since T, E and I cannot be in the 2nd position, and the position of the unknown 5th letter is known, only N can be there.

 

This gives us:

 

T is in the 3rd or 5th position

E is in the 1st or 3rd position

I is in the 1st or 5th position

N is in the 2nd position

 

Plugging TINE? into a scrabble helper give you all possible words made of TINE and a random 5th letter. Remove all the possibilities that contain an eliminated letter leaving UNTIE UNITE TWINE and FEINT. Unfortunately none of these can be correct because the first 3 end in E, which is definitely not in the last letter position and the last option has E as the second letter, when we know that N is the second letter.

 

If we assume that my initial assumption the X was incorrect and E was correct was wrong, we get stuck with a contradiction reasonably quickly:

 

 

T_XE_ (0, 2, 3) (X is correct, E is eliminated)

 

which gives us:

 

PI_N_ (0, 2, 3) (P, I, or N) choose 2

_R_PE (0, 1, 4) (R or P) choose 1

_ _ _ _ _ (0, 0, 5)

PINT_ (0, 3, 2) (P, I, or N) choose 2

PRIME (0, 2, 3) (P, R, I, or M) choose 2

BR_KE (0, 1, 4) (B, R, or K) choose 1

_TRIP (0, 2, 3) (R, I, or P) choose 1

DE_TH (0, 2, 3) (D or H) choose 1

 

Taking these two

_TRIP (0, 2, 3) (R, I, or P) choose 1

PI_N_ (0, 2, 3) (P, I, or N) choose 2

 

we know that either P or I must be correct, which means that R must be incorrect:

 

_R_PE (0, 1, 4) (R or P) choose 1. Therefore, P must be correct.

 

Take these two:

 

PINT_ (0, 3, 2) (P, I, or N) choose 2

PRIME (0, 2, 3) (P, I, or M) choose 2

Since we've decided that P is correct, I must be correct here, eliminating both N and M and telling us that both P and I are present in the word, which can't be right, because of :

 

_TRIP (0, 2, 3) (I or P) choose 1.

 

Daily Dare Neomysterion, could you double check your numbers please?

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Thanks :D I think I got a bit obsessed when I couldn't figure it out, I'm usually able to solve these kinds of things easily, especially with so many clues :P I didn't think anyone would read all of it, but thanks for confirming that it all made sense.

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Uh. O.O

 

Great logic there.

 

I did find one mistake. Those are not the only possible words, because Entei could be one of them (Entei is a Pokemon) So Neomysterion was correct, in his numbers from my understanding, but A for effort. ^_^

 

So I'm just gonna go with ENTEI

 

If it's not right, then I'm gonna shoot something

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Entei is correct!

 

Eli Goldsworthy gets the next round!

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