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Posted

Check this out, my math teacher showed me it the other day.

 

Suppose...

 

x=1

now multiply both sides by x. (x^2 is x squared)

x^2=x

now subtract 1 from both sides.

(x^2) - 1 = x - 1

[(x^2) - 1] factors as (x-1)(x+1)

(x-1)(x+1)=x-1

divide both sides by (x-1).

x+1=1

solve.

x=0.

 

Now plug that back into x=1 and you find that x=0.

 

Neat, huh?

 

Anyone have any others like this?

Posted

Wow. I didn't think that could happen. I guess someone got bored. xD

Posted

I can prove that 2 = 1.

 

a=1 b=1

 

so we conclude that:

a=b

 

multiply both sides by a:

a^2=ab

 

subtract both sides by b squared:

a^2 - b^2=ab - b^2

 

factor both sides:

( a-b ) ( a+b ) = b ( a-b )

 

divide both sides by ( a-b ):

( a+b ) = b

 

so,

1+1=1

 

2=1

 

*gasp*

Posted

How are your teachers finding this stuff? o_O

Posted

I found that one on youtube. :) :P I must have been bored.

Posted

Hmm. I guess I can't argue with that. I usually looked up random dance videos.

 

One was on Caramell Dansen, if you've heard that song before.

 

I'm just wondering how long it took someone to prove that 0=1 and 2=1. x_x

Posted

There is actually a flaw in mine, that makes it false, which is why it uses a's and b's. :P So, mine is just a mind trick really.

Posted

Hmm, I'm not even going to try to figure out the flaw. *brainfart*

Posted

Well, after looking at Mike's there is the same flaw in his too. ;) Brownie points to who ever posts it.

Posted

x=1

now multiply both sides by x. (x^2 is x squared)

x^2=x

now subtract 1 from both sides.

(x^2) - 1 = x - 1

[(x^2) - 1] factors as (x-1)(x+1)

(x-1)(x+1)=x-1

divide both sides by (x-1).

x+1=1

solve.

x=0.

 

So, technically I posted the flaw. Brownie points, please. ^_^ xD

Posted

You can have 1 brownie point for being a smart alack. HOWEVER. Post why these statements are false for MORE brownie points.

Posted

I thought I had it, but I can't figure it out. Someone else try. x_x

Posted
Is it for the sheer fact that 1 cannot be 0?

 

I also know the 0!=1

 

That is true, but what is the reason that makes the statements above false. There is something that is mathematically wrong with the statements.

Posted

o_x I can't believe I didn't see that before. Is that right, TJ?

 

By the way, I like your avatar, ffchild. ;)

Posted
It's pretty simple. It says to divide both sides by (x-1). X = 1, right? 1-1=0. You can't divide anything by zero.

 

And the winner is.... "ffchild"! Congratulations. You cannot divide anything by zero - it's undefined. :)

 

You can X brownie points. ;)

Posted

x=1, and I have 1 brownie point for being the jester that I am.

 

Nah, no more math tonight. x_x

Posted

*headdesk* Darn it, I should have gotten on TDN instead of finishing all those assignments. :P I love maths stuff like this.

Posted

Would it not be seven and five are thirteen. Seven plus five equals thirteen.. Ohh crap, now I am just confusing myself!!!

Posted

Eww, maths. I hate it, but it's not like I'm doing that for A-Level or anything...

 

But really it's just the magical abilities of 0 and 1. Technically, 0 isn't a number, but let's not confuse things.

 

I could show you how 0.99 recurring equals 1, but that'd be boring and you'll know it already... :P

Posted

Oh please, spare us, Matt. I'm still suffering from the 0=1 problem. x_x

Posted

Well I actually find this kind of thing fun. :P And I do already know how to show that 0.99 recurring is 1 (I also learned the logic that explains why it works). XD

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